rustHow to borrow a string in Rust
Rust provides a way to borrow a string using the &
operator. This operator allows you to borrow a string without taking ownership of it.
Example:
let s1 = String::from("hello");
let s2 = &s1;
The output of the example code is:
No output
The ## Code explanation
let s1 = String::from("hello");
: This line creates aString
object with the valuehello
.let s2 = &s1;
: This line creates a reference to theString
objects1
and assigns it tos2
.
Helpful links
Related
- How to borrow as static in Rust
- How to borrow with lifetime in Rust
- When to use borrow in Rust
- Example of borrow_mut in Rust
- How to borrow struct field in Rust
- Rust partial borrow example
- How to borrow moved value in Rust
- How to borrow from iterator in Rust
- How to borrow option value in Rust
- How to borrow hashmap in Rust
More of Rust
- How to replace a capture group using Rust regex?
- How to replace strings using Rust regex?
- How to get all matches from a Rust regex?
- How to match the end of a line in a Rust regex?
- How to escape dots with regex in Rust?
- How to use regex to match a double quote in Rust?
- How to calculate the inverse of a matrix in Rust?
- Bitwise XOR operator usage in Rust
- How to convert a Rust HashMap to a BTreeMap?
- How to replace all using regex in Rust?
See more codes...