rustHow to borrow a string in Rust
Rust provides a way to borrow a string using the & operator. This operator allows you to borrow a string without taking ownership of it.
Example:
let s1 = String::from("hello");
let s2 = &s1;
The output of the example code is:
No output
The ## Code explanation
let s1 = String::from("hello");: This line creates aStringobject with the valuehello.let s2 = &s1;: This line creates a reference to theStringobjects1and assigns it tos2.
Helpful links
Related
- Rust unsafe borrow example
- Rust partial borrow example
- How borrow instead of move in Rust
- How to borrow from iterator in Rust
- How to borrow with lifetime in Rust
- How to return borrow in Rust
- How to borrow hashmap in Rust
- How to borrow as static in Rust
- When to use borrow in Rust
- How to borrow vector element in Rust
More of Rust
- How to use regex to match a double quote in Rust?
- How to create a HashMap of structs in Rust?
- How to replace a capture group using Rust regex?
- How to match the end of a line in a Rust regex?
- How to modify an existing entry in a Rust HashMap?
- How do I identify unused variables in Rust?
- How to use negation in Rust regex?
- Regex example to match multiline string in Rust?
- How to use a Rust HashMap in a struct?
- How do I use a variable number of arguments in Rust?
See more codes...