rustHow to replace a capture group using Rust regex?
Replacing a capture group using Rust regex is a simple process. The replace_all
method of the Regex
type can be used to replace a capture group with a given string.
Example code
let re = Regex::new(r"(\d+)").unwrap();
let result = re.replace_all("My number is 123", "456");
Output example
My number is 456
The code above creates a new Regex
object with the pattern (\d+)
which captures any sequence of digits. The replace_all
method is then used to replace the captured group with the string 456
.
Code explanation
let re = Regex::new(r"(\d+)").unwrap();
- creates a newRegex
object with the pattern(\d+)
which captures any sequence of digits.let result = re.replace_all("My number is 123", "456");
- uses thereplace_all
method to replace the captured group with the string456
.
Helpful links
Related
- How to split a string with Rust regex?
- How to get a capture group using Rust regex?
- How to match whitespace with a regex in Rust?
- How to match a URL with a regex in Rust?
- How to replace all matches using Rust regex?
- How to replace strings using Rust regex?
- How to use Unicode in a regex in Rust?
- How to find the first match in a Rust regex?
- How to escape parentheses in a Rust regex?
More of Rust
- How to use non-capturing groups in Rust regex?
- How to split a string with Rust regex?
- How to get a capture group using Rust regex?
- How to create a new Rust HashMap with values?
- How to match whitespace with a regex in Rust?
- How to match a URL with a regex in Rust?
- How to replace all matches using Rust regex?
- How to get all matches from a Rust regex?
- How to get an entry from a HashSet in Rust?
See more codes...