rustHow to borrow with lifetime in Rust
Rust provides a powerful feature called 'lifetimes' which allows you to borrow data from one part of your code and use it in another. This is done by specifying a lifetime for a reference, which is a period of time during which the reference is valid.
fn main() {
let x = 5;
let y = &x;
println!("x = {}", x);
println!("y = {}", y);
}
Output example
x = 5
y = 5
The code above shows how to borrow with lifetime in Rust. The let x = 5 statement creates a variable x with the value 5. The let y = &x statement creates a reference y to the variable x. The & symbol is used to create a reference. The lifetime of the reference y is the same as the lifetime of the variable x.
List of ## Code explanation
let x = 5: creates a variablexwith the value5let y = &x: creates a referenceyto the variablex&symbol: used to create a referenceprintln!("x = {}", x): prints the value ofxprintln!("y = {}", y): prints the value ofy
Helpful links
Related
- How borrow instead of move in Rust
- How to borrow hashmap in Rust
- When to use borrow in Rust
- How to borrow from vector in Rust
- How to borrow int in Rust
- How to borrow moved value in Rust
- How to borrow vector element in Rust
- Rust unsafe borrow example
- How to borrow struct field in Rust
- How to return borrow in Rust
More of Rust
- How to match a URL with a regex in Rust?
- How to replace a capture group using Rust regex?
- How to use non-capturing groups in Rust regex?
- How to split a string with Rust regex?
- Regex example to match multiline string in Rust?
- How to make regex case insensitive in Rust?
- How to use negation in Rust regex?
- How to use regex lookbehind in Rust?
- How to use regex captures in Rust?
- How to match whitespace with a regex in Rust?
See more codes...