rustHow to pass a Rust slice as an argument?
Passing a Rust slice as an argument is done by using the &[T]
syntax. This syntax indicates that a reference to a slice of type T
is being passed.
Example
fn print_slice(slice: &[i32]) {
println!("{:?}", slice);
}
fn main() {
let arr = [1, 2, 3];
print_slice(&arr);
}
Output example
[1, 2, 3]
Code explanation
fn print_slice(slice: &[i32])
: This is a function that takes a reference to a slice of typei32
as an argument.let arr = [1, 2, 3]
: This creates an array of typei32
with the values1
,2
, and3
.print_slice(&arr)
: This passes a reference to the arrayarr
to the functionprint_slice
.
Helpful links
Related
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- How to convert a slice into an iter in Rust?
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- How to iterate over a Rust slice with an index?
- How to map a Rust slice?
- How to check for equality between Rust slices?
- How to declare a Rust slice?
- How to convert a Rust slice to a fixed array?
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See more codes...