rustHow to pass a Rust slice as a function parameter?
Passing a Rust slice as a function parameter is done by using the &[T] syntax. This syntax indicates that the function takes a slice of type T. For example:
fn print_slice(slice: &[i32]) {
for item in slice {
println!("{}", item);
}
}
let arr = [1, 2, 3];
print_slice(&arr);
Output example
1
2
3
fn print_slice(slice: &[i32]): This declares a function calledprint_slicethat takes a slice of typei32as a parameter.let arr = [1, 2, 3]: This creates an array of typei32with the values1,2, and3.print_slice(&arr): This passes the arrayarras a parameter to the functionprint_slice.
Helpful links
Related
- How to convert a Rust slice of u8 to u32?
- How to calculate the sum of a Rust slice?
- How to shift elements in a Rust slice?
- Does Rust perform bounds checking on slices?
- How to map a Rust slice?
- How to split a Rust slice?
- How to iterate over a Rust slice?
- How to convert a Rust slice to a fixed array?
- How to convert a Rust slice of u8 to a string?
- How to convert a Rust slice to a tuple?
More of Rust
- How to replace all matches using Rust regex?
- How to convert a u8 slice to a hex string in Rust?
- Rust HashMap example
- How to convert Rust bytes to a struct?
- How to use non-capturing groups in Rust regex?
- How to extend a Rust HashMap?
- Yield example in Rust
- How to use regex to match a group in Rust?
- How to perform matrix operations in Rust?
- How do I print the type of a variable in Rust?
See more codes...