rustHow to convert struct to protobuf in Rust
Converting a struct to protobuf in Rust is done using the prost crate.
To convert a struct to protobuf, the struct must first be annotated with #[derive(Message)] and the fields must be annotated with #[prost(...)].
Example code
#[derive(Message)]
struct MyStruct {
#[prost(int32, tag = "1")]
my_field: i32,
}
The #[derive(Message)] annotation tells the compiler to generate code to serialize and deserialize the struct into protobuf. The #[prost(...)] annotation tells the compiler how to serialize and deserialize the field.
The generated code can then be used to convert the struct to protobuf:
let my_struct = MyStruct { my_field: 42 };
let mut buf = Vec::new();
my_struct.encode(&mut buf).unwrap();
The encode method serializes the struct into protobuf and writes it to the buf vector.
Related
- How to init zero struct in Rust
- How to copy struct in Rust
- How to sort a struct in Rust
- How to update struct in Rust
- Example of struct private field in Rust
- Example of struct with vector field in Rust
- How to convert struct to bytes in Rust
- How to get struct length in Rust
- Example of Rust struct with closure
More of Rust
- Regex example to match multiline string in Rust?
- How to use regex captures in Rust?
- How to use binary regex in Rust?
- How to print a Rust HashMap?
- How to use regex to match a double quote in Rust?
- How to replace a capture group using Rust regex?
- How to match the end of a line in a Rust regex?
- How to match a URL with a regex in Rust?
- How to use regex with bytes in Rust?
- How to make regex case insensitive in Rust?
See more codes...