rustHow to copy pointer in Rust
In Rust, pointers can be copied by using the .clone()
method. This method creates a deep copy of the pointer, meaning that the new pointer will point to the same memory address as the original pointer. To demonstrate this, consider the following ## Code example:
let mut x = 5;
let mut y = &mut x;
let z = y.clone();
*y = 10;
println!("x = {}", x);
println!("y = {}", *y);
println!("z = {}", *z);
Output example
x = 10
y = 10
z = 5
Explanation
In this example, x
is a mutable variable with an initial value of 5
. y
is a mutable pointer to x
, and z
is a clone of y
. The value of x
is then changed to 10
using the *y
syntax, which dereferences y
and assigns the new value to x
. The output of the code shows that x
and y
have the same value of 10
, while z
still has the original value of 5
. This demonstrates that z
is a deep copy of y
, and that the two pointers point to the same memory address.
Relevant links
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