rustHow borrow instead of move in Rust
Rust provides a powerful feature called borrow
which allows you to access data without taking ownership of it. This is done by creating a reference to the data, which can be used to read or modify the data without taking ownership.
let mut x = 5;
let y = &x;
println!("x = {}", x);
println!("y = {}", y);
Output example
x = 5
y = 5
The code above creates a mutable variable x
and a reference y
to x
. The reference y
can be used to access the value of x
without taking ownership of it.
The following ## Code explanation
let mut x = 5;
: This creates a mutable variablex
with the value5
.let y = &x;
: This creates a referencey
to the variablex
.println!("x = {}", x);
: This prints the value ofx
to the console.println!("y = {}", y);
: This prints the value ofy
to the console.
For more information about borrowing in Rust, please refer to the Rust Book.
Related
- How to borrow vector element in Rust
- When to use borrow in Rust
- How to borrow with lifetime in Rust
- How to borrow hashmap in Rust
- How to borrow struct field in Rust
- How to return borrow in Rust
- Rust partial borrow example
- How to borrow int in Rust
- How to borrow iterator in Rust
- Example of borrow_mut in Rust
More of Rust
- How to match whitespace with a regex in Rust?
- How to replace a capture group using Rust regex?
- How to split a string with Rust regex?
- How to iterate over a Rust slice with an index?
- How to use negation in Rust regex?
- How to use regex captures in Rust?
- Regex example to match multiline string in Rust?
- How to get a capture group using Rust regex?
- How to use modifiers in a Rust regex?
- How to create a HashMap of structs in Rust?
See more codes...